Optimal. Leaf size=276 \[ \frac{\left (a+b x^2\right )^{3/2} \sqrt{c+d x^2} \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right )}{192 b^2 d^3}-\frac{\sqrt{a+b x^2} \sqrt{c+d x^2} (b c-a d) \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right )}{128 b^2 d^4}+\frac{(b c-a d)^2 \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b} \sqrt{c+d x^2}}\right )}{128 b^{5/2} d^{9/2}}-\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2} (3 a d+7 b c)}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d} \]
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Rubi [A] time = 0.32544, antiderivative size = 276, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.269, Rules used = {446, 90, 80, 50, 63, 217, 206} \[ \frac{\left (a+b x^2\right )^{3/2} \sqrt{c+d x^2} \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right )}{192 b^2 d^3}-\frac{\sqrt{a+b x^2} \sqrt{c+d x^2} (b c-a d) \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right )}{128 b^2 d^4}+\frac{(b c-a d)^2 \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b} \sqrt{c+d x^2}}\right )}{128 b^{5/2} d^{9/2}}-\frac{\left (a+b x^2\right )^{5/2} \sqrt{c+d x^2} (3 a d+7 b c)}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d} \]
Antiderivative was successfully verified.
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Rule 446
Rule 90
Rule 80
Rule 50
Rule 63
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{x^5 \left (a+b x^2\right )^{3/2}}{\sqrt{c+d x^2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x^2 (a+b x)^{3/2}}{\sqrt{c+d x}} \, dx,x,x^2\right )\\ &=\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}+\frac{\operatorname{Subst}\left (\int \frac{(a+b x)^{3/2} \left (-a c-\frac{1}{2} (7 b c+3 a d) x\right )}{\sqrt{c+d x}} \, dx,x,x^2\right )}{8 b d}\\ &=-\frac{(7 b c+3 a d) \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \operatorname{Subst}\left (\int \frac{(a+b x)^{3/2}}{\sqrt{c+d x}} \, dx,x,x^2\right )}{96 b^2 d^2}\\ &=\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{192 b^2 d^3}-\frac{(7 b c+3 a d) \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}-\frac{\left ((b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{\sqrt{a+b x}}{\sqrt{c+d x}} \, dx,x,x^2\right )}{128 b^2 d^3}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^2} \sqrt{c+d x^2}}{128 b^2 d^4}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{192 b^2 d^3}-\frac{(7 b c+3 a d) \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}+\frac{\left ((b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx,x,x^2\right )}{256 b^2 d^4}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^2} \sqrt{c+d x^2}}{128 b^2 d^4}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{192 b^2 d^3}-\frac{(7 b c+3 a d) \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}+\frac{\left ((b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x^2}\right )}{128 b^3 d^4}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^2} \sqrt{c+d x^2}}{128 b^2 d^4}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{192 b^2 d^3}-\frac{(7 b c+3 a d) \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}+\frac{\left ((b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x^2}}{\sqrt{c+d x^2}}\right )}{128 b^3 d^4}\\ &=-\frac{(b c-a d) \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \sqrt{a+b x^2} \sqrt{c+d x^2}}{128 b^2 d^4}+\frac{\left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \left (a+b x^2\right )^{3/2} \sqrt{c+d x^2}}{192 b^2 d^3}-\frac{(7 b c+3 a d) \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{48 b^2 d^2}+\frac{x^2 \left (a+b x^2\right )^{5/2} \sqrt{c+d x^2}}{8 b d}+\frac{(b c-a d)^2 \left (35 b^2 c^2+10 a b c d+3 a^2 d^2\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b} \sqrt{c+d x^2}}\right )}{128 b^{5/2} d^{9/2}}\\ \end{align*}
Mathematica [A] time = 0.574768, size = 231, normalized size = 0.84 \[ \frac{3 (b c-a d)^{5/2} \left (3 a^2 d^2+10 a b c d+35 b^2 c^2\right ) \sqrt{\frac{b \left (c+d x^2\right )}{b c-a d}} \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x^2}}{\sqrt{b c-a d}}\right )-b \sqrt{d} \sqrt{a+b x^2} \left (c+d x^2\right ) \left (3 a^2 b d^2 \left (5 c-2 d x^2\right )+9 a^3 d^3+a b^2 d \left (-145 c^2+92 c d x^2-72 d^2 x^4\right )+b^3 \left (-70 c^2 d x^2+105 c^3+56 c d^2 x^4-48 d^3 x^6\right )\right )}{384 b^3 d^{9/2} \sqrt{c+d x^2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.03, size = 770, normalized size = 2.8 \begin{align*}{\frac{1}{768\,{b}^{2}{d}^{4}}\sqrt{b{x}^{2}+a}\sqrt{d{x}^{2}+c} \left ( 96\,{x}^{6}{b}^{3}{d}^{3}\sqrt{bd}\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}+144\,{x}^{4}a{b}^{2}{d}^{3}\sqrt{bd}\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}-112\,{x}^{4}{b}^{3}c{d}^{2}\sqrt{bd}\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}+12\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{x}^{2}{a}^{2}b{d}^{3}\sqrt{bd}-184\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{x}^{2}ac{b}^{2}{d}^{2}\sqrt{bd}+140\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{x}^{2}{c}^{2}{b}^{3}d\sqrt{bd}+9\,{d}^{4}\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){a}^{4}+12\,{a}^{3}c\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) b{d}^{3}+54\,\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){a}^{2}{c}^{2}{b}^{2}{d}^{2}-180\,a{c}^{3}\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){b}^{3}d+105\,{b}^{4}\ln \left ( 1/2\,{\frac{2\,d{x}^{2}b+2\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ){c}^{4}-18\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{a}^{3}{d}^{3}\sqrt{bd}-30\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{a}^{2}cb{d}^{2}\sqrt{bd}+290\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}a{c}^{2}{b}^{2}d\sqrt{bd}-210\,\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}{c}^{3}{b}^{3}\sqrt{bd} \right ){\frac{1}{\sqrt{bd{x}^{4}+ad{x}^{2}+bc{x}^{2}+ac}}}{\frac{1}{\sqrt{bd}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.27163, size = 1265, normalized size = 4.58 \begin{align*} \left [\frac{3 \,{\left (35 \, b^{4} c^{4} - 60 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} + 4 \, a^{3} b c d^{3} + 3 \, a^{4} d^{4}\right )} \sqrt{b d} \log \left (8 \, b^{2} d^{2} x^{4} + b^{2} c^{2} + 6 \, a b c d + a^{2} d^{2} + 8 \,{\left (b^{2} c d + a b d^{2}\right )} x^{2} + 4 \,{\left (2 \, b d x^{2} + b c + a d\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c} \sqrt{b d}\right ) + 4 \,{\left (48 \, b^{4} d^{4} x^{6} - 105 \, b^{4} c^{3} d + 145 \, a b^{3} c^{2} d^{2} - 15 \, a^{2} b^{2} c d^{3} - 9 \, a^{3} b d^{4} - 8 \,{\left (7 \, b^{4} c d^{3} - 9 \, a b^{3} d^{4}\right )} x^{4} + 2 \,{\left (35 \, b^{4} c^{2} d^{2} - 46 \, a b^{3} c d^{3} + 3 \, a^{2} b^{2} d^{4}\right )} x^{2}\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c}}{1536 \, b^{3} d^{5}}, -\frac{3 \,{\left (35 \, b^{4} c^{4} - 60 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} + 4 \, a^{3} b c d^{3} + 3 \, a^{4} d^{4}\right )} \sqrt{-b d} \arctan \left (\frac{{\left (2 \, b d x^{2} + b c + a d\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c} \sqrt{-b d}}{2 \,{\left (b^{2} d^{2} x^{4} + a b c d +{\left (b^{2} c d + a b d^{2}\right )} x^{2}\right )}}\right ) - 2 \,{\left (48 \, b^{4} d^{4} x^{6} - 105 \, b^{4} c^{3} d + 145 \, a b^{3} c^{2} d^{2} - 15 \, a^{2} b^{2} c d^{3} - 9 \, a^{3} b d^{4} - 8 \,{\left (7 \, b^{4} c d^{3} - 9 \, a b^{3} d^{4}\right )} x^{4} + 2 \,{\left (35 \, b^{4} c^{2} d^{2} - 46 \, a b^{3} c d^{3} + 3 \, a^{2} b^{2} d^{4}\right )} x^{2}\right )} \sqrt{b x^{2} + a} \sqrt{d x^{2} + c}}{768 \, b^{3} d^{5}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{5} \left (a + b x^{2}\right )^{\frac{3}{2}}}{\sqrt{c + d x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.23056, size = 410, normalized size = 1.49 \begin{align*} \frac{\sqrt{b^{2} c +{\left (b x^{2} + a\right )} b d - a b d} \sqrt{b x^{2} + a}{\left (2 \,{\left (b x^{2} + a\right )}{\left (4 \,{\left (b x^{2} + a\right )}{\left (\frac{6 \,{\left (b x^{2} + a\right )}}{b d} - \frac{7 \, b^{3} c d^{5} + 9 \, a b^{2} d^{6}}{b^{3} d^{7}}\right )} + \frac{35 \, b^{4} c^{2} d^{4} + 10 \, a b^{3} c d^{5} + 3 \, a^{2} b^{2} d^{6}}{b^{3} d^{7}}\right )} - \frac{3 \,{\left (35 \, b^{5} c^{3} d^{3} - 25 \, a b^{4} c^{2} d^{4} - 7 \, a^{2} b^{3} c d^{5} - 3 \, a^{3} b^{2} d^{6}\right )}}{b^{3} d^{7}}\right )} - \frac{3 \,{\left (35 \, b^{4} c^{4} - 60 \, a b^{3} c^{3} d + 18 \, a^{2} b^{2} c^{2} d^{2} + 4 \, a^{3} b c d^{3} + 3 \, a^{4} d^{4}\right )} \log \left ({\left | -\sqrt{b x^{2} + a} \sqrt{b d} + \sqrt{b^{2} c +{\left (b x^{2} + a\right )} b d - a b d} \right |}\right )}{\sqrt{b d} d^{4}}}{384 \, b{\left | b \right |}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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